We know that, in English alphabets, there are (5 vowels + 21 consonants) = 26 letters. So, total number of outcomes in English alphabets is,n(S) = 26

Let E = Event of choosing an English alphabet, which is a consonant

= {b, c, d, f, g, h, j, k, l, m, n, p, q, r, s t, v, w, x, y, z}

∴ n(E) = 21

Hence, required probability