If ∆ABC ∼ ∆DFE, ∠A = 30°, ∠C = 50°, AB = 5 cm, AC = 8 cm and DF = 7.5 cm. Then, which of the following is true?
Given: ∆ABC ∼ ∆DFE,
As ∆ABC ∼ ∆DFE so, by the property of Corresponding angles of similar triangles,
We have,
∠A = ∠D = 30° (Corresponding angles)
∠C = ∠E = 50° (Corresponding angles)
We know that sum of angles of a triangle = 180°
So,
∴ ∠B = ∠F = 180°- (30° + 50°) = 100°
Also Given,
AB = 5 cm,
AC = 8 cm and
DF = 7.5 cm
Hence,
DE = 12 cm, and ∠F = 100°