In figure, if ∠D = ∠C, then it is true that ∆ADE ∼ ∆ACB? Why?
(True)
In ∆ADE and ∆ACB,
Given,
∠D = ∠C
∠A = ∠A [common angle]
As we know sum of all the angles of a triangle is equals to 180∘.
So, by angle sum property of triangle the third angle of both triangles must be equal.
∠E = ∠B
∴ ∆ADE ∼ ∆ACB [by AAA similarity criterion]