Diagonals of a trapezium PQRS intersect each other at at the point 0, PQ‖RS and PQ = 3RS. Find the ratio of the areas of ∆POQ and ∆ROS.
Given,
PQRS is a trapezium in which PQ‖RS and PQ = 3RS
In ∆POQ and ∆ROS,
∠SOR = ∠QOP [vertically opposite angles]
∠SRP = ∠RPQ [alternate angles]
∴ ∆POQ ∼ ∆ROS [by AAA similarity criterion]
By property of area of similar triangle,
[from Equation (i)]
Hence, the required ratio is 9:1.