If ∆ABC ∼ ∆DEF, AB = 4 cm, DE = 6, EF = 9 cm and FD = 12 cm, then find the perimeter of ∆ABC.
Given,
AB = 4 cm,
DE = 6 cm
EF = 9 cm and
FD = 12 cm
Also,
∆ABC ∼ ∆DEF
We have,
By taking first two terms, we have
And by taking last two terms, we have,
Now,
Perimeter of ∆ABC = AB + BC + AC
= 4 + 6 + 8 = 18 cm
Thus, the perimeter of the triangle is 18 cm.