In given figure, if ∠A = ∠C, AB = 6 cm, BP = 15 cm, AP = 12 cm and CP = 4 cm, then find the lengths of PD and CD.
Given,
∠A = ∠C,
AB = 6 cm, BP = 15 cm,
AP = 12 cm
CP = 4 cm
In ∆APB and ∆CPD,
∠A = ∠C [given]
∠APB = ∠CPD [vertically opposite angles]
∴ By AAA similarity criteria,
∆APD ∼ ∆CPD
By taking first two terms,
By taking first and last terms,
Hence,
length of PD = 5 cm
length of CD = 2 cm