In the given figure AB || CD. If ∠OAB = 124°, ∠OCD = 136°, then ∠AOC = ?
Draw a line EF such that EF || AB and EF || CD crossing point O.
FOC +
OCD = 180o (Sum of consecutive interior angles is 180o)
FOC = 180 – 136 = 44o
EF || AB such that AO is traversal.
OAB +
FOA = 180o(Sum of consecutive interior angles is 180o)
FOA = 180 – 124 = 56o
AOC =
FOC +
FOA
= 56 + 44
=100o