In the given figure, AB || CD. If ∠AOC = 30° and ∠OAB = 100°, then ∠OCD = ?
From O, draw E such that OE || CD || AB.
OE || CD and OC is traversal.
So,
DCO + COE = 180 (co –interior angles)
x + COE = 180
COE = (180 – x)
Now, OE || AB and AO is the traversal.
BAO + AOE = 180 (co –interior angles)
BAO + AOC + COE = 180
100 + 30 + (180 – x) = 180
180 – x = 50
X = 180 – 50 = 130O