In ΔABC, if ∠A + ∠B = 125° and ∠A + ∠C = 113°, then ∠A = ?
A + 
B + 
C = 180
C = 180 – 125 = 55o
A + 
C =113o
A =113 – 55 =58o
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In ΔABC, if ∠A + ∠B = 125° and ∠A + ∠C = 113°, then ∠A = ?
A + B + C = 180
C = 180 – 125 = 55o
A + C =113o
A =113 – 55 =58o