Side BC of ΔABC has been produced to D on left hand side and to E on right hand side such that ABD = 125° and ACE = 130°. Then A = ?

ABD + ABC = 180 (Linear pair of angles)


ABC = 180o – 125o=55o


ACE + ACB = 180 (Linear pair of angles)


ACB = 180o – 130o=50o


As we know that


ACB + ABC + BAC = 180o


BAC = 180 – 55 – 50


=75o

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