In the given figure, ∠ BAC = 30°, ∠ ABC = 50 ° and ∠ CDE = 40°. Then ∠ AED = ?

Question

Philoid · Accepted Answer

ACB + ABC + BAC =180

ACB = 180 – 50 – 30 = 100^o(Sum of angles of triangle is 180)

ACB + ACD = 180 (linear pair of angles)

ACD = 180 – 100 = 80^o

In triangle ECD,

ECD + CDE + DEC = 180

DEC = 180 – 80 – 40

= 60^o

DEC + AED = 180^o(linear pair of angles)

AED = 180^o – 60^o

= 120^o