In the given figure, BO and CO are the bisectors of ∠B and ∠C respectively. If ∠A = 50°, then ∠BOC = ?
In ∆ABC,
∠A + ∠B + ∠C=180°
50° + ∠B + ∠C=180°
∠B + ∠C=180°−50°=130°
∠B = 65°
∠C = 65°
Now in ∆OBC,
∠OBC + ∠OCB + ∠BOC=180°
∠BOC = 180° – 65° (∠OBC + ∠OCB = 65 because O is bisector of ∠B and ∠C)
= 115°