In the given figure, AB || CD. If ∠ EAB = 50° and ∠ ECD = 60°, then ∠ AEB = ?

Question

Philoid · Accepted Answer

AB || CD and BC is traversal.

So, ∠DCB = ∠ABC = 60^o

Now in triangle AEB, we have

∠ABE + ∠BAE + ∠AEB =180^o

∠AEB =180^o – 60^o – 50^o

= 70^o