In a ΔABC its is given that A : B : C = 3 : 2 : 1 and CD AC. Then ECD = ?

As per question,



So,


A = 90o


B = 60o


C = 30o


ACB + ACD + ECD = 180o (sum of angles on straight line)


ECD = 180o – 90o – 30o


= 60o

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