In the given figure, AB || DC, ∠BAD = 90°, ∠CBD = 28° and ∠BCE = 65°. Then ∠ABD = ?
∠BCE = ∠ABC =65o (Alternate Angles)
∠ABC = ∠ABD + ∠DBC
65o = ∠ABD + 28o
∠ABD = 65 – 28
= 37o