In the given figure, sides CB and BA of ΔABC have been produced to D and E respectively such that ∠ABD = 110° and ∠CAE = 135°. Then ∠ACB = ?
∠ABC = 180 – 110 = 700 (Linear pair of angles)
∠BAC = 180 – 135 = 450 (Linear pair of angles)
So,
In Triangle ABC, we have
∠ABC + ∠BAC + ∠ACB = 180o
∠ACB = 180 – 70 – 45 = 650