In ΔABC, BD ⊥ AC, ∠ CAE = 30° and ∠ CBD = 40°. Then ∠ AEB = ?

Question

Philoid · Accepted Answer

In triangle BDC,

∠B= 40, ∠D = 90

So, ∠C = 180 –(90 + 40)

= 50°

Now in triangle AEC,

∠C= 50, ∠A = 30

So, ∠E = 180 – (50 + 30)

= 100°

Thus, ∠AEB = 180 – 100 (Sum of linear pair is 180°)

= 80°