In the given figure, AB || CD || EF, EA ⊥ AB and BDE is the transversal such that ∠DEF = 55°. Then ∠AEB = ?
According to question
AB || CD || EF and
So, ∠D = ∠B (Corresponding angles)
According to question CD || EF and BE is the traversal then,
∠D + ∠E = 180 (Interior angle on the same side is supplementary)
So, ∠D = 180 – 55 = 125o
And ∠B = 125o
Now, AB || EF and AE is the traversal.
So, ∠BAE + ∠FEA = 180 (Interior angle on the same side of traversal is supplementary)
90 + x + 55 = 180
X + 145 = 180
X= 180 – 145 = 35o