The sides BC, BA and CA of ΔABC have been produced to D, E and F respectively, as shown in the given figure. Then, ∠B = ?
BAC = 35o (opposite pair of angles)
BCD = 180 – 110 = 70o (linear pair of angles)
Now, in Triangle ABC we have,
A + B + C = 180o
35 + B + 70 = 180
B = 180 – 105 = 75o