Match the following columns:
Column I | Column II |
(a) In the given figure, ABC is a straight line. Then, ∠ACD = …..
| (p) 110° |
(b) In the given figure, ∠AOC = (2x – 10)° and ∠BOC = (3x – 10)°. Then, ∠AOD = …
| (q) 85° |
(c) In the given figure, side BC of ΔABC has been produced to D. If ∠A = 65° and ∠B = 60°, then ∠ACD = ?
| (r) 72° |
(d) In the given figure, AB || DE, ∠CDE = 50° and ∠BAC = 45°, then ∠ACB = ….
| (s) 125° |
The correct answer is:
A. – …….., B. – ……….,
C. – ………, D. – ……….,
(a) – (r), (b) – (p), (c) – (s), (d) – (q)
(a) – (r)
2x + 3x = 180 (linear pair of angles)
5x =180
X = 36
2x = 2 X 36 = 72
(b) – (p)
2x – 10 + 3x – 10 = 180 (linear pair of angles)
5x – 20 =180
5x = 200
x = 40
AOD = 3x – 10 (opposite angles are equal)
= 120 – 10
= 110
(c) – (s)
C = 180 – (A + B) (sum of angles triangle is 180)
= 180 – (60 + 65)
= 55
ACD = 180 – 55 (sum of linear pair of angles is 180)
= 180 – 55
= 125
(d) – (q)
B = D) (alternate interior angles)
= 55
ACB = 180 – (55 + 40) (sum of angles of triangle is 180)
= 180 – 95
= 85