In a ΔABC, if ∠ A – ∠ B = 40° and ∠ B – ∠ C = 10°, find the measure of ∠ A, ∠ B and ∠ C.

Question

Philoid · Accepted Answer

A = B + 40

C = B – 10

A + B + C = 180

B + 40 + B + B – 10 = 180

3B + 30 = 180

3B = 180 – 30 = 150

B = 50^O

So, A = B + 40 = 90^O

C = B – 10 = 40^O