In the given figure, AOB is a straight line. If ∠AOC = 40°, ∠COD = 4x° and ∠BOD = 3xׄ°, then x = ?
40 + 4x + 3x = 180 (sum of angles on a straight line)
7x + 40 =180
7x = 180 – 40
X = 140/ 7 = 20
7
In the given figure, AOB is a straight line. If ∠AOC = 40°, ∠COD = 4x° and ∠BOD = 3xׄ°, then x = ?
40 + 4x + 3x = 180 (sum of angles on a straight line)
7x + 40 =180
7x = 180 – 40
X = 140/ 7 = 20