In the given figure, AB || CD || EF. If ABC = 85°, BCE = x° and CEF = 130°, then x = ?


According to question,


AB || EF


EF || CD (AB is produced to F, CF is traversal)


FEC=130o


Now, BFC + BFO = 180o(Sum of angles of Linear pair is 180o)


BFO = 180o – 130o = 50o


Now in triangle BOF, we have


ABO = BFO + BOF


85 = 50 + BOF


BOF = 85 – 50 =35o


So, x = o

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