Of the three angles of a triangle, one is twice the smallest and another one is thrice the smallest. Find the angles.
Let x be the common multiple.
So, angles will be x, 2x and 3x
X + 2x + 3x = 180
6x = 180
X =30
2x = 2 X 30 = 60
3x = 3 X 30 = 90
So, Angles are 30O,60O and 90O