Of the three angles of a triangle, one is twice the smallest and another one is thrice the smallest. Find the angles.

Let x be the common multiple.


So, angles will be x, 2x and 3x


X + 2x + 3x = 180


6x = 180


X =30


2x = 2 X 30 = 60


3x = 3 X 30 = 90


So, Angles are 30O,60O and 90O


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