In the given figure, ABCD is a parallelogram in which ∠BAD = 75° and ∠CBD = 60°. Then, ∠BDC = ?
It is given in the question that,
In parallelogram ABCD: ∠ BAD = 75o, ∠ CBD = 60o
Now, ∠ DAB = ∠ DCB = 75o (Opposite angles)
Also, in triangle DBC we know that sum of angles of a triangle is 180o
∠ DBC + ∠ BDC + ∠ DCB = 180o
60o + ∠ BDC + 75o = 180o
135o + ∠ BDC = 180o
∠ BDC = 180o – 135o
∠ BDC = 45o
Hence, option (C) is correct