If an angle of a parallelogram is two-third of its adjacent angle, the smallest angle of the parallelogram is

We know that,

Sum of two adjacent angles is equal to 180o


∴∠ A + B = 180o


According to the condition given in the question, we have


A = x° then B = 2/3 x°


x° + 2x/3 ° = 180°


5x/3 ° = 180°


x =


x = 540°/5


x = 108o


∴∠ A = 108o and,


B = 2/3 × 108°


B = 2× 36° = 72°


Thus, the smallest angle = B = 72o


Hence, option (C) is correct

17