If an angle of a parallelogram is two-third of its adjacent angle, the smallest angle of the parallelogram is
We know that,
Sum of two adjacent angles is equal to 180o
∴∠ A + ∠ B = 180o
According to the condition given in the question, we have
∠ A = x° then ∠ B = 2/3 x°
∴ x° + 2x/3 ° = 180°
5x/3 ° = 180°
⇒ x =
⇒ x = 540°/5
⇒ x = 108o
∴∠ A = 108o and,
∠ B = 2/3 × 108°
∠ B = 2× 36° = 72°
Thus, the smallest angle = ∠ B = 72o
Hence, option (C) is correct