If one angle of a parallelogram is 24o less than twice the smallest angle, then the largest angle of the parallelogram is
As per the question,
Let the smallest angle be x° and the largest angle be (2x – 24)°
Since, the sum of adjacent angles of a parallelogram is 180°
∴ x + (2x – 24) = 180°
3x – 24 = 180°
x = 68°
Hence, the largest angle is: 2x – 24 = 2(68) – 24 = 136 – 24 = 112
∴Option A is correct