In the given figure, ABCD is a parallelogram in which ∠BDC = 45° and ∠BAD = 75°. Then, ∠CBD = ?

Question

In the given figure, ABCD is a parallelogram in which ∠ BDC = 45° and ∠ BAD = 75°. Then, ∠ CBD = ?

Philoid · Accepted Answer

As per the question,

∠ BAD = ∠ BCD = 75° (opposite angles of parallelogram)

Now, in ΔBCD,

∠BCD + ∠CBD + ∠BCD = 180°

45 + ∠CBD + 75 = 180°

∠CBD = 60°

∴ Option C is correct