In the given figure, ABCD is a parallelogram, M is the mid-point of BD and BD bisects B as well as D. Then, AMB = ?

Since, ABCD is a parallelogram,

∴∠B = D (opposite angle)


1/2 B = 1/2 D


ADB = ABD


ADB is an isosceles triangle.


Since, M is the midpoint of BD


AM is a median of ΔADB.


Now, AMB = 90° (AM is perpendicular to BD)


Option C is correct

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