In the given figure, AD is a median of ΔABC and E is the mid-point of AD. If BE is joined and produced to meet AC in F, then AF = ?
Let G be the mid-point of FC and join DG
In ∆BCF,
G is the mid-point of FC and D is the mid-point of BC
Thus, DG|| BF
DG || EF
Now, In ∆ ADG,
E is the mid-point of AD and EF is parallel to DG.
Thus, F is the mid-point of AG.
AF = FG = GC [G is the mid-point of FC]
Hence, AF = AC
∴ Option B is correct