If A, B, C and D of a quadrilateral ABCD taken in order, are in the ratio 3 : 7 : 6: 4, then ABCD is a

Let the required angles be 3x, 7x, 6x and 4x

3x + 7x + 6x + 4x = 360° (Sum of angles of quadrilateral)


20x = 360°


x = 18°


Hence, angles are:


3x = 3 18° = 54°


7x = 7 18° = 126°


6x = 6 18° = 108°


4x = 4 18° = 72°


Now we can observe that, 54° + 126° = 180° and 72° + 108° = 180°


Thus, ABCD is a trapezium.


Hence option C is correct.

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