In the given figure ABCD, DCFE and ABFE are parallelograms. Show that ar(ΔADE) = ar(ΔBCF).

Question

Philoid · Accepted Answer

Now, here in ∆ADE and ∆BCF,

AD = BC (Opposite sides of parallelogram ABCD

DE = CF (Opposite sides of parallelogram DCEF)

AE = BF (Opposite sides of parallelogram ABFE)

∴ By SSS axiom,

∆ADE ≅ ∆BCF

And,

ar(∆ADE) = ar(∆BCF) (By cpct)