In a frequency distribution, the mild-value of a class is 10 and width of each class is 6. The lower limit of the class is

Let the upper limit of class = u


Let lower limit of class = l


Mild value = 10 (given)


We know that,


Mild value = 1/2 (u + l)


10 = 1/2 (u + l)


= u + l = 20..............(i)


Width of class = 6 (given)


= u – l = 6 ................(ii)


Subtracting equation (ii) from equation (i), we get,


2l = 14


= l = 14/2 = 7.


lower limit = 7.

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