The mid-value of a class interval is 42 and the class size is 10. The lower and upper limits are

Question

Philoid · Accepted Answer

Given,

Mid value of class interval = 42

Class size = 10

Let the upper limit of class = u

Let lower limit of class = l

We know that,

Mild value = 1/2 (u + l)

42 = 1/2 (u + l)

= u + l = 84..............(i)

Class size = u – l

= u – l = 10 (given)

Adding equation (ii) & equation (i), we get,

2u = 94

⇒ u = 94/2 = 47.

From equation (ii)

u – l = 10

l = 47 – 10 = 37.