To divide a line segment AB in the ratio 5:7, first a ray AX is drawn, so that ∠ BAX is an acute angle and then at equal distances points are marked on the ray AX such that the minimum number of these points is

Question

Philoid · Accepted Answer

Given, a line segment AB in the ratio 5:7

A:B = 5:7

Now,

Draw a ray AX which makes an acute angle ∠BAX, then mark A+B points at equal distance. And, here, A=5 and B=7

Hence, minimum number of these points

= A+B

= 5+7

=12

To divide a line segment AB in the ratio 5:7, first a ray AX is drawn, so that ∠BAX is an acute angle and then at equal distances points are marked on the ray AX such that the minimum number of these points is