To divide a line segment AB in the ratio 5:6, draw a ray AX such that BAX is an acute angle, then draw a ray BY parallel to AX and the points A1, A2, A3,............... and B1, B2, B3,............. are located to equal distances on ray AX and BY, respectively. Then the points joined are

Given, a line segment AB in the ratio 5:7

A:B = 5:7

Steps of construction:

1. Draw a ray AX, an acute BAX.

2. Draw a ray BY AX,

3. Now, locate the points A1,A2,A3,A4 and A5 on AX and B1,B2,B3,B4,B5 and B6 (Because A:B = 5:7)

4. Join A5B6.

A5B6 intersect AB at a point C.

AC:BC= 5:6