To divide a line segment AB in the ratio 5:6, draw a ray AX such that ∠ BAX is an acute angle, then draw a ray BY parallel to AX and the points A 1 , A 2 , A 3 ,............... and B 1 , B 2 , B 3 ,............. are located to equal distances on ray AX and BY, respectively. Then the points joined are

Question

Philoid · Accepted Answer

Given, a line segment AB in the ratio 5:7

A:B = 5:7

Steps of construction:

1. Draw a ray AX, an acute BAX.

2. Draw a ray BY AX,
ABY = BAX.

3. Now, locate the points A₁,A₂,A₃,A₄ and A₅ on AX and B₁,B₂,B₃,B₄,B₅ and B₆ (Because A:B = 5:7)

4. Join A₅B₆.

A₅B₆ intersect AB at a point C.

AC:BC= 5:6

To divide a line segment AB in the ratio 5:6, draw a ray AX such that ∠BAX is an acute angle, then draw a ray BY parallel to AX and the points A1, A2, A3,............... and B1, B2, B3,............. are located to equal distances on ray AX and BY, respectively. Then the points joined are