To divide a line segment AB in the ratio 5:6, draw a ray AX such that ∠BAX is an acute angle, then draw a ray BY parallel to AX and the points A_{1}, A_{2}, A_{3},............... and B_{1}, B_{2}, B_{3},............. are located to equal distances on ray AX and BY, respectively. Then the points joined are

Given, a line segment AB in the ratio 5:7

A:B = 5:7

Steps of construction:

1. Draw a ray AX, an acute BAX.

2. Draw a ray BY AX,

ABY = BAX.

3. Now, locate the points A_{1},A_{2},A_{3},A_{4} and A_{5} on AX and B_{1},B_{2},B_{3},B_{4},B_{5} and B_{6} (Because A:B = 5:7)

4. Join A_{5}B_{6}.

A_{5}B_{6} intersect AB at a point C.

AC:BC= 5:6

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