Draw a line segment of length 7 cm. From a point P on it which divides it into the ratio 3:5.

Steps of construction

1. Draw a line AB=7 cm.

2. Draw a ray AX, (Acute BAX).

3. Along AX, divide (3+5) 8 equals points

A1, A2, A3, A4, A5, A6, A7, A8

AA1=A1A2=A2A3=A3A4=A4A5=A5A6=A6A7= A7A8

4. Join A8B.

5. Draw A3CA8B meeting AB at C.

AC : CB=3:5

Let, AA1=A1A2=A2A3=A3A4=........=A7A8=x

In ∆ABA8,


AC:CB = 3:5