Draw a line segment of length 7 cm. From a point P on it which divides it into the ratio 3:5.

Steps of construction

1. Draw a line AB=7 cm.



2. Draw a ray AX, (Acute ∠BAX).



3. Along AX, divide (3+5) 8 equals points


A1, A2, A3, A4, A5, A6, A7, A8


AA1=A1A2=A2A3=A3A4=A4A5=A5A6=A6A7= A7A8


4. Join A8B.


5. Draw A3CA8B meeting AB at C.


AC : CB=3:5



Let, AA1=A1A2=A2A3=A3A4=........=A7A8=x


In ∆ABA8,


A3CA8B


∴


AC:CB = 3:5


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