The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is

Question

Philoid · Accepted Answer

Clearly, the given bucket is in the form of frustum of a cone.

And we know

Curved surface area of frustum of a cone = πl(r₁ + r₂)

Where, l = slant height,

r₁ and r₂ are radii (r₁ > r₂)

For given bucket,

Radius of top, r₁ = 28 cm

Radius of bottom, r₂ = 7 cm

Slant height, l = 45 cm

Therefore,

Curved surface area of bucket = π(45)(28 + 7)

= 4950 cm²

So, the curved surface area of bucket is 4950 cm^2.