By what number should 1365 be divided to get 31 quotient and 32 as remainder?
By Euclid’s division lemma -
x = bq + r ….(1)
where q is the quotient,
r is the remainder
and b is the divisor.
According to the question, x = 1365, r = 32, q = 31, b = ?.
Putting the values in equation(1) -
∴ 1365 = b(31) + 32
⇒ 31b = 1333
⇒ b = 43