In the adjoining figure, ΔABC is a right-angled triangle in which B = 90°, A= 30° and AC = 20 cm. Find (i) BC, (ii) AB.

Since, in a right angled triangle,


sin θ = Perpendicular / Hypotenuse ,


and cos θ = Base / Hypotenuse ,


where θ is the angle made between the hypotenuse and the base.


(i) In the given figure, sin 30° = BC/AC


1/2 = BC/20


(1/2) × 20 = BC


BC = 10 cm


(ii) Now, In the given figure, cos 30° = AB/AC


√3/2 = AB/20


(√3/2) × 20 = AB


AB = 10√3 cm


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