In the adjoining figure, ΔABC is a right-angled triangle in which B = 90°, ∠A= 30° and AC = 20 cm. Find (i) BC, (ii) AB.
Since, in a right angled triangle,
sin θ = Perpendicular / Hypotenuse ,
and cos θ = Base / Hypotenuse ,
where θ is the angle made between the hypotenuse and the base.
(i) ∴ In the given figure, sin 30° = BC/AC
⇒ 1/2 = BC/20
⇒ (1/2) × 20 = BC
⇒ BC = 10 cm
(ii) Now, In the given figure, cos 30° = AB/AC
⇒ √3/2 = AB/20
⇒ (√3/2) × 20 = AB
⇒ AB = 10√3 cm