Prove that:

sin (70°+θ) — cos (20° — θ) = 0

Consider L.H.S.

= sin (70°+θ) — cos (20° — θ)


= sin (70°+θ) — cos [90°-(70° + θ)]


= sin (70°+θ) — sin (70° + θ)


= 0 = R.H.S.


Hence, proved.

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