RS Aggarwal - Mathematics

Book: RS Aggarwal - Mathematics

Chapter: 12. Circles

Subject: Maths - Class 10th

Q. No. 9 of Multiple Choice Questions (MCQ)

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In the given figure, AB and AC are tangents to the circle with center O such that BAC = 40°. Then, BOC is equal to

As AB and AC are tangents to given circle,

We have,


[ Tangents drawn at a point on circle is perpendicular to the radius through point of contact]

So, OBA = OCA = 90°

In quadrilateral AOBC, By angle sum property of quadrilateral, we have,

OBA + OCA + BOC + BAC = 360°

90° + 90° + BOC + 40° = 360°

BOC = 140°

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