In the given figure, quad. ABCD is circumscribed, touching the circle at P, Q, R and S. If AP = 6 cm, BP = 5 cm, CQ = 3 cm and DR = 4 cm then perimeter of quad. ABCD is
As we know Tangents drawn from an external point are equal]
In the given Figure, we have
AP = AS = 6 cm [AP = 6 cm is given]
[∵ Tangents from point A]
BP = BQ = 5 cm [BP = 5 cm is given]
[∵ Tangents from point B]
CR = CQ = 3 cm [CQ = 3 cm is given]
[∵ Tangents from point C]
DR = DS = 4 cm ][DR = 4 cm is given]
[∵ Tangents from point D]
Now,
Perimeter of ABCD = AB + BC + CA + DA
= AP + BP + BQ + CQ + CR + DR + DS + AS
= 6 + 5 + 5 + 3 + 3 + 4 + 4 + 6 = 36 cm
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