In the given figure, if AB = AC, prove that BE = CE.

We know, that tangents drawn from an external point are equal.


AD = AF


[tangents from point A] [1]


BD = BE


[tangents from point B] [2]


CF = CE


[tangents from point C] [3]


Now,


AB = AC [Given] …[4]


Substracting [1] From [4]


AB - AD = AC - AF


BD = CF


BE = CE [From 2 and 3]


Hence Proved.


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