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In the given figure, if AB = AC, prove that BE = CE.
We know, that tangents drawn from an external point are equal.
AD = AF
[tangents from point A] [1]
BD = BE
[tangents from point B] [2]
CF = CE
[tangents from point C] [3]
Now,
AB = AC [Given] …[4]
Substracting [1] From [4]
AB - AD = AC - AF
BD = CF
BE = CE [From 2 and 3]
Hence Proved.