Construct an isosceles triangle whose base is 4.8 cm and whose vertical angle is 80°.
Steps of Construction
1. Draw a line segment BC = 4.8 cm
2. Since one of the angles is 80°, the sum of other two will be 100°.
3. It is isosceles so the other two angles will be 50° and 50°.
4. Draw a 50° angles at B and C each respectively.
5. Extend them such that they meet at A.
6. Join AB and AC.
Therefore, ΔPQR is the required isosceles triangle in which AB=AC.