Construct an isosceles triangle whose base is 4.8 cm and whose vertical angle is 80°.

Steps of Construction


1. Draw a line segment BC = 4.8 cm


2. Since one of the angles is 80°, the sum of other two will be 100°.


3. It is isosceles so the other two angles will be 50° and 50°.



4. Draw a 50° angles at B and C each respectively.


5. Extend them such that they meet at A.


6. Join AB and AC.



Therefore, ΔPQR is the required isosceles triangle in which AB=AC.


9