Construct a ΔABC whose perimeter is 12 cm and whose base angles are 45° and 60°.
Steps of construction
1. Draw a line segment PQ = AB + BC + CA = 12 cm.
2. Make ∠ LPQ= 45° and ∠ MQP = 60°
3. Now bisect ∠ LPQ and ∠ MQP such that their bisectors meet at A.
4. Draw perpendicular bisector of AP and AQ i.e. XY and ST intersecting PQ at B and C respectively.
5. Join AB and AC.