Construct a ΔABC in which B = 60°, C = 45° and the length of perpendicular from vertex A to base BC as 5 cm.

Steps of Construction


1. Draw a line segment XY.


2. Take any point P on XY and draw PQXY.


3. Along PQ, set off PA= 5 cm


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4. Through A, draw LMXY.


5. Construct LAB=60° and MAC=45° meeting XY at B and C respectively.


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Therefore, ΔABC is the required triangle.


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