Construct a ΔABC in which base BC = 5.2 cm, B = 60° and (AB + AC) = 7.6 cm.

Steps of Construction


1. Draw BC = 5.2 cm


2. Construct CBX=60°


3. Along BX set off BP = 7.6 cm


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4. Join CP.


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5. Draw the perpendicular bisector of CP to intersecting BP at A.


6. Join AC.



Therefore, ΔABC is the required triangle.


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