Construct a ΔABC in which base BC = 4.8 cm, ∠B = 45° and (AB – AC) = 2.5 cm.
Steps of Construction
1. Draw BC= 4.8 cm
2. Construct ∠CBX=45°
3. Along BX set off BP = 2.5 cm
4. Join PC
5. Draw the perpendicular bisector of PC meeting BP produced at A.
6. Join AC.
Therefore, ΔABC is the required triangle.