One zero of the polynomial 3x^{3} + 16x^{2} + 15x – 18 is 2/3. Find the other zeros of the polynomial.

It is given in the question that,

x = 2/3 is one of the zeros of the given polynomial 3x^{3} + 16x^{2} + 15x – 18

We have, x = 2/3

x –2/3 = 0

To find the quotient we have to divide the given polynomial by x – 2/3

Quotient = 3x^{2} + 18x + 27

∴ 3x^{2} + 18x + 27 = 0

3x^{2} + 9x + 9x + 27 = 0

3x (x + 3) + 9 (x + 3) = 0

(x + 3) (3x + 9) = 0

(x + 3) = 0 or (3x + 9) = 0

Hence, x = - 3 or x = - 3

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