One zero of the polynomial 3x3 + 16x2 + 15x – 18 is 2/3. Find the other zeros of the polynomial.
It is given in the question that,
x = 2/3 is one of the zeros of the given polynomial 3x3 + 16x2 + 15x – 18
We have, x = 2/3
x –2/3 = 0
To find the quotient we have to divide the given polynomial by x – 2/3
Quotient = 3x2 + 18x + 27
∴ 3x2 + 18x + 27 = 0
3x2 + 9x + 9x + 27 = 0
3x (x + 3) + 9 (x + 3) = 0
(x + 3) (3x + 9) = 0
(x + 3) = 0 or (3x + 9) = 0
Hence, x = - 3 or x = - 3
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